export type Data = { [key: string]: unknown } export type UnionToIntersection = ( U extends any ? (k: U) => void : never ) extends (k: infer I) => void ? I : never // Conditional returns can enforce identical types. // See here: https://github.com/Microsoft/TypeScript/issues/27024#issuecomment-421529650 // prettier-ignore type Equal = (() => U extends Left ? 1 : 0) extends (() => U extends Right ? 1 : 0) ? true : false; export type HasDefined = Equal extends true ? false : true // If the the type T accepts type "any", output type Y, otherwise output type N. // https://stackoverflow.com/questions/49927523/disallow-call-with-any/49928360#49928360 export type IfAny = 0 extends 1 & T ? Y : N export type LooseRequired = { [P in string & keyof T]: T[P] }