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      {\displaystyle{\displaystyle\int_{0}^{\infty}\frac{x^{\alpha}}{\left(-x;q%
      \right)_{\infty}}\mathop{L^{(\alpha)}_{m}\/}\nolimits\!\left(x;q\right)\mathop%
      {L^{(\alpha)}_{n}\/}\nolimits\!\left(x;q\right)\,dx{}=\frac{\left(q^{-\alpha};%
      q\right)_{\infty}}{\left(q;q\right)_{\infty}}\frac{\left(q^{\alpha+1};q\right)%
      _{n}}{\left(q;q\right)_{n}q^{n}}\mathop{\Gamma\/}\nolimits\!\left(-\alpha%
      \right)\mathop{\Gamma\/}\nolimits\!\left(\alpha+1\right)\,\delta_{m,n}}}
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