Intersection

by Pineapple @Pineapple0919

takes an Array T containing several arrays or any type element including the union type, and returns a new union containing all intersection elements. ```ts type Res = Intersection<[[1, 2], [2, 3], [2, 2]]>; // expected to be 2 type Res1 = Intersection<[[1, 2, 3], [2, 3, 4], [2, 2, 3]]>; // expected to be 2 | 3 type Res2 = Intersection<[[1, 2], [3, 4], [5, 6]]>; // expected to be never type Res3 = Intersection<[[1, 2, 3], [2, 3, 4], 3]>; // expected to be 3 type Res4 = Intersection<[[1, 2, 3], 2 | 3 | 4, 2 | 3]>; // expected to be 2 | 3 type Res5 = Intersection<[[1, 2, 3], 2, 3]>; // expected to be never ```